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PHP字符串的递增和递减示例 - 站长搜索
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PHP字符串的递增和递减示例

PHP 2014-12-26 06:48:04 转载来源: 网络整理/侵权必删

本文是一个PHP字符串的递增和递减示例,感兴趣的同学参考下. 今天看到php手册上有这么一段话: “在处理字符变量的算数运算时,PHP 沿袭了 Perl 的习惯,而非 C 的。例如,在 Perl 中 $a = 'Z'; $a++; 将把 $a 变成'AA',而在 C 中,a = 'Z'; a++; 将把 a 变成 '['('Z' 的 ASCII 值是 90,'[' 的 ASCII 值是 91)

本文是一个PHP字符串递增递减示例,感兴趣的同学参考下.


今天看到php手册上有这么一段话:

“在处理字符变量的算数运算时,PHP 沿袭了 Perl 的习惯,而非 C 的。例如,在 Perl 中 $a = 'Z'; $a++; 将把 $a 变成'AA',而在 C 中,a = 'Z'; a++; 将把 a 变成 '['('Z' 的 ASCII 值是 90,'[' 的 ASCII 值是 91)。注意字符变量只能递增,不能递减,并且只支持纯字母(a-z 和 A-Z)。递增/递减其他字符变量则无效,原字符串没有变化。”

也就是说:


for($i = 'A'; $i <= 'Z'; $i++) {
echo $i;
//if( $i == 'ZZZ') die();
}


结果是:ABCDEFGHIJKLMNOPQRSTUVWXYZAAABACADAEAFAGAHAIAJAKALAMANAOAPAQARASATAUA…………

还有字符串变量不能递减:


$a = 'Z';
--$a;
echo $a; // Z


这也说明了$a++或++$a,不能要 $a = $a + 1;来解释


$a = $b = 'Z';
$a = $a + 1;
echo $a; //1
++$b;
echo $b; //AA

标签: PHP 字符串 递增 递减 示例


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