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php获取301跳转目标URL方法实例

PHP 2014-12-15 05:45:04 转载来源: 网络整理/侵权必删

本文为大家提供的是一个php获取301跳转目标URL方法实例,感兴趣的同学参考下. /**  * get_redirect_url()  * Gets the address that the provided URL redirects to,  * or FALSE if there's no redirect

本文为大家提供的是一个php获取301跳转目标URL方法实例,感兴趣的同学参考下.


/**
 * get_redirect_url()
 * Gets the address that the provided URL redirects to,
 * or FALSE if there's no redirect.
 *
 * @param string $url
 * @return string
 */
function get_redirect_url($url){
    $redirect_url = null;

    $url_parts = @parse_url($url);
    if (!$url_parts) return false;
    if (!isset($url_parts['host'])) return false; //can't process relative URLs
    if (!isset($url_parts['path'])) $url_parts['path'] = '/';

    $sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80), $errno, $errstr, 30);
    if (!$sock) return false;

    $request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?'.$url_parts['query'] : '') . " HTTP/1.1rn";
    $request .= 'Host: ' . $url_parts['host'] . "rn";
    $request .= "Connection: Closernrn";
    fwrite($sock, $request);
    $response = '';
    while(!feof($sock)) $response .= fread($sock, 8192);
    fclose($sock);
    if (preg_match('/^Location: (.+?)$/m', $response, $matches)){
        if ( substr($matches[1], 0, 1) == "/" )
            return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]);
        else
            return trim($matches[1]);

    } else {
        return false;
    }

}
/**
 * get_all_redirects()
 * Follows and collects all redirects, in order, for the given URL.
 *
 * @param string $url
 * @return array
 */
function get_all_redirects($url){
    $redirects = array();
    while ($newurl = get_redirect_url($url)){
        if (in_array($newurl, $redirects)){
            break;
        }
        $redirects[] = $newurl;
        $url = $newurl;
    }
    return $redirects;
}
 


php实现用socket获取301跳转地址,可以提取跳转过程中的url


标签: php 获取 跳转 目标 URL 方法 实例


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